2023 July-December

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Question 1 (a): What are the characteristics of statistics?

To be considered statistics, information must possess several key features:

  1. Aggregates of Individuals: Statistics must deal with groups rather than isolated cases.
  2. Numerical Expression: Data must be presented in the form of numerical figures.
  3. Multiplicity of Causes: Statistical outcomes are generally influenced by various factors.
  4. Standard of Accuracy: The data collected must meet reasonable accuracy standards.
  5. Pre-determined Purpose: Collection should be driven by a specific, previously decided objective.
  6. Comparability: The data must allow for meaningful comparison with other datasets.

Question 1 (b): Mention different types of data.

Data is classified based on five primary criteria:


Question 1 (c): Briefly discuss data based on source and scale.

Data Based on Source:

Data Based on Scale:


Question 2 (a): Illustrate the classical and statistical probability with their limitations.

1. Mathematical (Classical) Definition: If a trial results in n exhaustive, mutually exclusive, and equally likely cases, and m of them are favorable to event A, the probability is: $$P(A) = \frac{\text{Favorable outcomes (m)}}{\text{Total outcomes (n)}}$$

2. Statistical (Empirical) Definition: If an event A occurs r times in n independent trials, the probability is defined as the limit of the relative frequency (r/n) as n tends toward infinity: $$P(A) = \lim_{n \to \infty} \frac{r}{n}$$


Question 2 (b): State the different types of laws of probability. State and prove the theorem of total probability for two not mutually exclusive events. What will happen when the events are mutually exclusive?

Types of Laws: The two primary laws are the Additive Law (Theorem of Total Probability) and the Multiplicative Law (Theorem of Compound Probability).

Theorem of Total Probability (Additive Law): The probability of at least one of two not mutually exclusive events occurring is the sum of their individual probabilities minus the probability of their joint occurrence: $$P(A_1 + A_2) = P(A_1) + P(A_2) - P(A_1 A_2)$$

Proof:

  1. Consider a Venn diagram where A1 and A2 overlap.
  2. The area of A1 is the sum of the part unique to A1 (A1A2¯) and the overlap (A1A2). So, P(A1)=P(A1A2)+P(A1A2¯) (Eq. i).
  3. Similarly, the area of A2 is P(A2)=P(A1A2)+P(A1¯A2) (Eq. ii).
  4. The total area covered by both events (A1+A2) consists of three non-overlapping parts: P(A1+A2)=P(A1A2¯)+P(A1A2)+P(A1¯A2) (Eq. iii).
  5. Adding (Eq. i) and (Eq. ii) gives: P(A1)+P(A2)=[P(A1A2)+P(A1A2¯)]+[P(A1A2)+P(A1¯A2)].
  6. This sum includes the overlap (A1A2) twice. By substituting (Eq. iii) into this equation, we get: P(A1)+P(A2)=P(A1+A2)+P(A1A2).
  7. Rearranging the terms yields: ** P(A1+A2)=P(A1)+P(A2)−P(A1A2) **.

Mutually Exclusive Case: If events are mutually exclusive, they cannot occur simultaneously, meaning P(A1A2)=0. In this case, the law simplifies to: $$P(A_1 + A_2) = P(A_1) + P(A_2)$$


Question 2 (c): Urn Probability Problem.

Problem: 16 balls (8 White, 5 Red, 3 Blue). Draw 2 balls.

Step 1: Calculate Total Outcomes (n): We draw 2 balls from 16. Using combinations (16C2): $$n = \frac{16 \times 15}{2 \times 1} = 120 \text{ ways}$$

Step 2: Calculate Favorable Outcomes for Same Color (m): The balls can be both White, both Red, or both Blue.

Step 3: Solve for (i) Same Color: $$P(\text{Same Color}) = \frac{m}{n} = \mathbf{\frac{41}{120} \approx 0.3417}$$

Step 4: Solve for (ii) Different Colors: This is the complement of drawing the same color. $$P(\text{Different Colors}) = 1 - P(\text{Same Color}) = 1 - \frac{41}{120} = \mathbf{\frac{79}{120} \approx 0.6583}$$